erweitern ((3+2x)^3)/6

Lösung

erweitern

\frac{( 3 + 2 x ) ^{3}}{6}

\frac{4 x ^{3}}{3} + 6 x^{2} + 9 x + \frac{9}{2}

Schritte zur Lösung

\frac{( 3 + 2 x ) ^{3}}{6}

(3 + 2 x)^{3} = 27 + 54 x + 36 x^{2} + 8 x^{3}

= \frac{27 + 54 x + 36 x ^{2} + 8 x ^{3}}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{27 + 54 x + 36 x ^{2} + 8 x ^{3}}{6} = \frac{27}{6} + \frac{54 x}{6} + \frac{36 x ^{2}}{6} + \frac{8 x ^{3}}{6}

= \frac{27}{6} + \frac{54 x}{6} + \frac{36 x ^{2}}{6} + \frac{8 x ^{3}}{6}

\frac{27}{6} = \frac{9}{2}

\frac{54 x}{6} = 9 x

\frac{36 x ^{2}}{6} = 6 x^{2}

\frac{8 x ^{3}}{6} = \frac{4 x ^{3}}{3}

= \frac{9}{2} + 9 x + 6 x^{2} + \frac{4 x ^{3}}{3}

Rewrite in standard form

= \frac{4 x ^{3}}{3} + 6 x^{2} + 9 x + \frac{9}{2}

e x p an d \frac{24}{( s + 1 ) ( s ^{2} + 6 s + 13 )}

e x p an d \frac{1 + x ^{2}}{1 + 4 x}

e x p an d \frac{1}{s ^{3} ( s + 1 )}

e x p an d (2 - t) (cos (2 π t))

e x p an d - 1 (- \frac{x}{5} + y - 2 + \frac{1}{5} = 0)