展开 (e^{x+y}+ye^y)dx+(xe^y-1)dy

解答

展开

(e^{x + y} + y e^{y}) d x + (x e^{y} - 1) d y

e^{x + y} d x + e^{y} y d x + e^{y} x d y - d y

求解步骤

(e^{x + y} + y e^{y}) d x + (x e^{y} - 1) d y

= (e^{x + y} + e^{y} y) d x + (e^{y} x - 1) d y

乘开

d x (e^{x + y} + y e^{y}) : e^{x + y} d x + e^{y} y d x

= e^{x + y} d x + e^{y} y d x + (x e^{y} - 1) d y

乘开

d y (x e^{y} - 1) : e^{y} x d y - d y

= e^{x + y} d x + e^{y} y d x + e^{y} x d y - d y

e x p an d - 3 j (3 j^{2})

e x p an d \frac{( 1000 + n ^{2} ) ^{2}}{1000000}

e x p an d Z ((n - 1) a^{n - 1})

e x p an d f (35 (t - \frac{4}{5})) H (t - \frac{4}{5})

e x p an d - \frac{( h - 8 ) ( h - 12 )}{4}