erweitern ((2x+1)(3x-1))/6

Lösung

erweitern

\frac{( 2 x + 1 ) ( 3 x - 1 )}{6}

x^{2} + \frac{x}{6} - \frac{1}{6}

Schritte zur Lösung

\frac{( 2 x + 1 ) ( 3 x - 1 )}{6}

Multipliziere aus

(2 x + 1) (3 x - 1) : 6 x^{2} + x - 1

= \frac{6 x ^{2} + x - 1}{6}

Wende Bruchregel an:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{6 x ^{2} + x - 1}{6} = \frac{6 x ^{2}}{6} + \frac{x}{6} - \frac{1}{6}

= \frac{6 x ^{2}}{6} + \frac{x}{6} - \frac{1}{6}

Teile die Zahlen:

\frac{6}{6} = 1

= x^{2} + \frac{x}{6} - \frac{1}{6}

e x p an d \frac{( 4 x ^{4} + 1 ) ^{2}}{16 x ^{4}}

e x p an d \frac{c}{( x + 2 ) ( x + 3 )}

e x p an d \frac{4 x ^{2} + 16 x - 21}{( x + 2 ) ^{2}}

e x p an d (2 - x) e^{x + 2}

e x p an d e^{s} (1 - e^{- s})