展开 (8(s^6+4s^4+10s^2+8))/(s^3(s^2+4)^3)

解答

展开

\frac{8 ( s ^{6} + 4 s ^{4} + 10 s ^{2} + 8 )}{s ^{3} ( s ^{2} + 4 ) ^{3}}

\frac{8 s ^{6} + 32 s ^{4} + 80 s ^{2} + 64}{s ^{9} + 12 s ^{7} + 48 s ^{5} + 64 s ^{3}}

求解步骤

\frac{8 ( s ^{6} + 4 s ^{4} + 10 s ^{2} + 8 )}{s ^{3} ( s ^{2} + 4 ) ^{3}}

(s^{2} + 4)^{3} = s^{6} + 12 s^{4} + 48 s^{2} + 64

= \frac{8 ( s ^{6} + 4 s ^{4} + 10 s ^{2} + 8 )}{s ^{3} ( s ^{6} + 12 s ^{4} + 48 s ^{2} + 64 )}

乘开

s^{3} (s^{6} + 12 s^{4} + 48 s^{2} + 64) : s^{9} + 12 s^{7} + 48 s^{5} + 64 s^{3}

= \frac{8 ( s ^{6} + 4 s ^{4} + 10 s ^{2} + 8 )}{s ^{9} + 12 s ^{7} + 48 s ^{5} + 64 s ^{3}}

乘开

8 (s^{6} + 4 s^{4} + 10 s^{2} + 8) : 8 s^{6} + 32 s^{4} + 80 s^{2} + 64

= \frac{8 s ^{6} + 32 s ^{4} + 80 s ^{2} + 64}{s ^{9} + 12 s ^{7} + 48 s ^{5} + 64 s ^{3}}

e x p an d \frac{( - 10 x ^{2} + 24 x + 152 )}{( x ^{2} - 4 x + 20 ) ^{2}}

e x p an d (x + 1, y - z sin (z^{2}), z + y sin (z^{2})) \cdot x

e x p an d \frac{s - 5}{( s - 6 ) ( s ^{2} - 8 s + 16 )}

e x p an d 1 \cdot (x + λ y + z = λ)

e x p an d - \frac{4}{( x + 1 ) ( x + 2 ) ( x - 1 )}