(\partial)/(\partial u)((x)(u+bv-x))

Lösung

\frac{\partial}{\partial u} ((x) (u + b v - x))

x

Schritte zur Lösung

\frac{\partial}{\partial u} ((x) (u + b v - x))

Behandle

b, x, v

als Konstanten

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= x \frac{\partial}{\partial u} (u + b v - x)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= x (\frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (b v) - \frac{\partial}{\partial u} (x))

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (b v) = 0

\frac{\partial}{\partial u} (x) = 0

= x (1 + 0 - 0)

Vereinfache

= x

e x p an d (4 tan (x) + 4) d x

e x p an d \frac{2 y ^{3} ( y - 1 )}{( 2 y - 1 )}

e x p an d \frac{e ^{- 4 x} + 3 x}{( x ) ( x ^{2} + 1 )}

e x p an d π (3 r + 8 s)^{2} \cdot (12 r + 32 s)

e x p an d (f \circ g) 3 (- x + 7) - 2