展开 (x^2+1)^2dx

解答

展开

(x^{2} + 1)^{2} d x

x^{4} d x + 2 x^{2} d x + d x

求解步骤

(x^{2} + 1)^{2} d x

(x^{2} + 1)^{2} = x^{4} + 2 x^{2} + 1

= (x^{4} + 2 x^{2} + 1) d x

打开括号

= d x x^{4} + d x \cdot 2 x^{2} + d x \cdot 1

= x^{4} d x + 2 x^{2} d x + 1 \cdot d x

乘以:

1 \cdot d x = d x

= x^{4} d x + 2 x^{2} d x + d x

e x p an d \frac{x - 4}{4 ( x - 4 ) ^{3}}

e x p an d \frac{f ( 4 x - 5 + h ) - 4 x - 5}{h}

e x p an d cos (x) d x + (1 + \frac{2}{y}) sin (x)

e x p an d \frac{3 ( - t ^{4} + 12 t ^{2} - 12 )}{2 t ^{2}}

e x p an d (1.45) (50)