展开 (14sin(θ))/((1+cos(θ))^2)

解答

展开

\frac{14 sin ( θ )}{( 1 + cos ( θ ) ) ^{2}}

\frac{14 sin ( θ )}{1 + 2 cos ( θ ) + cos ^{2} ( θ )}

求解步骤

\frac{14 sin ( θ )}{( 1 + cos ( θ ) ) ^{2}}

(1 + cos (θ))^{2} = 1 + 2 cos (θ) + cos^{2} (θ)

= \frac{14 sin ( θ )}{1 + 2 cos ( θ ) + cos ^{2} ( θ )}

\frac{\partial}{\partial y} ((x) (x^{2} + 2 - x y - y))

e x p an d (1 - t) s L + (1 - L) - \frac{( 1 - L ) ^{2}}{2} + xg

e x p an d x 3 (x^{2} + 1)^{2} + 3 (x^{2} + 1)^{2}

e x p an d (1 + t (x)^{2}) \frac{d ^{2}}{d t d x} (x) + x

e x p an d - \frac{3}{4} (e^{- x} - e^{3 x})