展开 e^{3x^2+x}(6x+1)

解答

展开

e^{3 x^{2} + x} (6 x + 1)

6 e^{3 x^{2} + x} x + e^{3 x^{2} + x}

求解步骤

e^{3 x^{2} + x} (6 x + 1)

使用分配律:

a (b + c) = ab + a c

a = e^{3 x^{2} + x}, b = 6 x, c = 1

= e^{3 x^{2} + x} \cdot 6 x + e^{3 x^{2} + x} \cdot 1

= 6 e^{3 x^{2} + x} x + 1 \cdot e^{3 x^{2} + x}

乘以:

1 \cdot e^{3 x^{2} + x} = e^{3 x^{2} + x}

= 6 e^{3 x^{2} + x} x + e^{3 x^{2} + x}

e x p an d \frac{3 ( x ^{2} + 2 ) ^{\frac{4}{3}} + 3}{2 ( x ^{2} + 2 ) ^{\frac{1}{3}}}

e x p an d (3 - 5 x e^{x}) (3 x + 2)

e x p an d (b^{2} + c^{2})^{2} + a^{2}

\frac{d ^{2}}{d x ^{2}} ((u (x)) (5.38 + 1.25 \cdot ln (x) - 250 x))

e x p an d \frac{( e ^{2} - 1 ) I n ^{2}}{2}