展开 ((x^2-8)^2)/2

解答

展开

\frac{( x ^{2} - 8 ) ^{2}}{2}

\frac{x ^{4}}{2} - 8 x^{2} + 32

求解步骤

\frac{( x ^{2} - 8 ) ^{2}}{2}

(x^{2} - 8)^{2} = x^{4} - 16 x^{2} + 64

= \frac{x ^{4} - 16 x ^{2} + 64}{2}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{x ^{4} - 16 x ^{2} + 64}{2} = \frac{x ^{4}}{2} - \frac{16 x ^{2}}{2} + \frac{64}{2}

= \frac{x ^{4}}{2} - \frac{16 x ^{2}}{2} + \frac{64}{2}

数字相除:

\frac{16}{2} = 8

= \frac{x ^{4}}{2} - 8 x^{2} + \frac{64}{2}

数字相除:

\frac{64}{2} = 32

= \frac{x ^{4}}{2} - 8 x^{2} + 32

e x p an d t^{4} (e^{\frac{11}{3}} + t^{2})

e x p an d (x + 5 y = - 15) \cdot (- 1)

e x p an d - \frac{j}{( 1 - 2 j ) \cdot ( 1 + 2 j )}

e x p an d \frac{d}{d x} \frac{( 50 ( x - 2 ) ^{3} )}{e ^{x}} + 10

e x p an d \frac{8}{( s - 2 ) ( s ^{2} - 4 s + 20 )}