展开 (36e^{4(t^2+6t)})*(2t+6)

解答

展开

(36 e^{4 (t^{2} + 6 t)}) \cdot (2 t + 6)

72 e^{4 t^{2} + 24 t} t + 216 e^{4 t^{2} + 24 t}

求解步骤

(36 e^{4 (t^{2} + 6 t)}) (2 t + 6)

使用分配律:

a (b + c) = ab + a c

a = (36 e^{4 (t^{2} + 6 t)}), b = 2 t, c = 6

= (36 e^{4 (t^{2} + 6 t)}) \cdot 2 t + (36 e^{4 (t^{2} + 6 t)}) \cdot 6

= 2 t (36 e^{4 (t^{2} + 6 t)}) + 6 (36 e^{4 (t^{2} + 6 t)})

化简

2 t (36 e^{4 (t^{2} + 6 t)}) + 6 (36 e^{4 (t^{2} + 6 t)}) : 72 e^{4 t^{2} + 24 t} t + 216 e^{4 t^{2} + 24 t}

= 72 e^{4 t^{2} + 24 t} t + 216 e^{4 t^{2} + 24 t}

\frac{d}{d t} ((m) (4 - 2 t))

e x p an d \frac{d x}{x ( ln ^{2} ( x ) + 4 )}

e x p an d \frac{11 s + 10}{s ( s + 25 )}

e x p an d \frac{2}{( 2 X - 1 )}

e x p an d \frac{2 e ^{- 4 t} - 13 y + 8 + 2 s}{s ( s + 4 )}