展开 ((5x+c)/2)^2

解答

展开

(\frac{5 x + c}{2})^{2}

\frac{25 x ^{2}}{4} + \frac{5 c x}{2} + \frac{c ^{2}}{4}

求解步骤

(\frac{5 x + c}{2})^{2}

使用指数法则:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 5 x + c ) ^{2}}{2 ^{2}}

(5 x + c)^{2} = 25 x^{2} + 10 c x + c^{2}

= \frac{25 x ^{2} + 10 c x + c ^{2}}{2 ^{2}}

2^{2} = 4

= \frac{25 x ^{2} + 10 c x + c ^{2}}{4}

使用分式法则:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{25 x ^{2} + 10 c x + c ^{2}}{4} = \frac{25 x ^{2}}{4} + \frac{10 c x}{4} + \frac{c ^{2}}{4}

= \frac{25 x ^{2}}{4} + \frac{10 c x}{4} + \frac{c ^{2}}{4}

消掉

\frac{10 c x}{4} : \frac{5 c x}{2}

= \frac{25 x ^{2}}{4} + \frac{5 c x}{2} + \frac{c ^{2}}{4}

e x p an d \frac{20 x ^{3}}{4 x}

e x p an d - 1 (y - x = 10)

\frac{d}{d y} ((x) (6 x + ln (6 y)))

e x p an d e^{4 x} \cdot 4 (x^{2} + 1) - 2 x e^{4 x}

e x p an d H^{2} + (0.1 t + 1)^{2}