展开 n^{1/2}(1+ln|n|)

解答

展开

n^{\frac{1}{2}} (1 + ln ∣ n ∣)

n^{\frac{1}{2}} + n^{\frac{1}{2}} ln ∣ n ∣

求解步骤

n^{\frac{1}{2}} (1 + ln ∣ n ∣)

使用分配律:

a (b + c) = ab + a c

a = n^{\frac{1}{2}}, b = 1, c = ln ∣ n ∣

= n^{\frac{1}{2}} \cdot 1 + n^{\frac{1}{2}} ln ∣ n ∣

= 1 \cdot n^{\frac{1}{2}} + n^{\frac{1}{2}} ln ∣ n ∣

乘以:

1 \cdot n^{\frac{1}{2}} = n^{\frac{1}{2}}

= n^{\frac{1}{2}} + n^{\frac{1}{2}} ln ∣ n ∣

e x p an d - \frac{t}{( t + x ) ( t - x )}

e x p an d \frac{1}{S ( S + 1 )}

e x p an d \frac{5 ( 2 ^{100} - 1 )}{2 ^{99}}

e x p an d - \frac{3 ( x - 4 )}{2}

e x p an d ((λ - 1) (4 λ - 3)) \cdot 4