展开 tan(4x)(1+sin(x)-1=0)

解答

展开

tan (4 x) (1 + sin (x) - 1 = 0)

tan (4 x) sin (x) = 0

求解步骤

tan (4 x) (1 + sin (x) - 1 = 0)

= tan (4 x) (1 + sin (x) - 1 \cdot 0 =)

打开括号

= tan (4 x) \cdot 1 + tan (4 x) sin (x) + tan (4 x) (- 1 = 0)

使用加减运算法则

+ (- a) = - a

1 \cdot tan (4 x) + tan (4 x) sin (x) - 1 \cdot tan (4 x) = 0

乘开

1 \cdot tan (4 x) + tan (4 x) sin (x) - 1 \cdot tan (4 x) : tan (4 x) sin (x)

tan (4 x) sin (x) = 0

e x p an d e^{- 3 x} (\frac{e ^{3 x} x}{3} - e^{3 x}) + \frac{1}{5} e^{5 x}

e x p an d \frac{( s + 1500 )}{s ( s + 200 )}

\frac{d ^{2}}{d x ^{2}} ((f (x)) (4 x^{2} - 5 x - 2))

e x p an d y^{3} (10 - 6 y + e^{- 3 x})

e x p an d [cos (2 t) \cdot u (t - 2 π)] [3 (1 - u (t - 2 π))]