erweitern ((2x-1)/(x+1))^2

Lösung

erweitern

(\frac{2 x - 1}{x + 1})^{2}

\frac{4 x ^{2} - 4 x + 1}{x ^{2} + 2 x + 1}

Schritte zur Lösung

(\frac{2 x - 1}{x + 1})^{2}

Wende Exponentenregel an:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 x - 1 ) ^{2}}{( x + 1 ) ^{2}}

(x + 1)^{2} = x^{2} + 2 x + 1

= \frac{( 2 x - 1 ) ^{2}}{x ^{2} + 2 x + 1}

(2 x - 1)^{2} = 4 x^{2} - 4 x + 1

= \frac{4 x ^{2} - 4 x + 1}{x ^{2} + 2 x + 1}

e x p an d \frac{2 ( x + 6 )}{( x + 4 ) ( x - 4 )}

e x p an d x (x^{2} + 3 x + 2)^{2}

e x p an d \frac{( x + 2 ) ( x + 1 )}{2}

e x p an d π (2 + ln (2 - 1))

e x p an d \frac{s ^{3} + 25 s + 2 s ^{2} + 55}{( s ^{2} + 2 s + 2 ) ( s ^{2} + 25 )}