展开 (((64x+32)(2x+1)))/2

解答

展开

\frac{( ( 64 x + 32 ) ( 2 x + 1 ) )}{2}

64 x^{2} + 64 x + 16

求解步骤

\frac{( 64 x + 32 ) ( 2 x + 1 )}{2}

分解

(64 x + 32) (2 x + 1) : 32 (2 x + 1)^{2}

= \frac{32 ( 2 x + 1 ) ^{2}}{2}

数字相除:

\frac{32}{2} = 16

= 16 (2 x + 1)^{2}

(2 x + 1)^{2} = 4 x^{2} + 4 x + 1

= 16 (4 x^{2} + 4 x + 1)

打开括号

= 16 \cdot 4 x^{2} + 16 \cdot 4 x + 16 \cdot 1

化简

16 \cdot 4 x^{2} + 16 \cdot 4 x + 16 \cdot 1 : 64 x^{2} + 64 x + 16

= 64 x^{2} + 64 x + 16

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