簡約 (4x)(3x+10)(2x)(x+20)

解

簡約

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

4^{\circ} \cdot 2^{\circ} x^{2 \circ} (x + 20)^{\circ} (3 x + 10)^{\circ}

解答ステップ

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

(4 x)^{\circ} = 4^{\circ} x^{\circ}

= 4^{\circ} x^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x)^{\circ} = 2^{\circ} x^{\circ}

= 4^{\circ} \cdot 2^{\circ} x^{\circ} x^{\circ} (3 x + 10)^{\circ} (x + 20)^{\circ}

指数の規則を適用する:

a^{b} \cdot a^{c} = a^{b + c}

x^{\circ} x^{\circ} = x^{\circ +\circ}

= 4^{\circ} (3 x + 10)^{\circ} \cdot 2^{\circ} x^{\circ +\circ} (x + 20)^{\circ}

類似した元を足す:

\circ + \circ = 2 \circ

= 4^{\circ} (3 x + 10)^{\circ} \cdot 2^{\circ} x^{2 \circ} (x + 20)^{\circ}