化简 (4x)(3x+10)(2x)(x+20)

解答

化简

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

4^{\circ} \cdot 2^{\circ} x^{2 \circ} (x + 20)^{\circ} (3 x + 10)^{\circ}

求解步骤

(4 x)^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(4 x)^{\circ} = 4^{\circ} x^{\circ}

= 4^{\circ} x^{\circ} (3 x + 10)^{\circ} (2 x)^{\circ} (x + 20)^{\circ}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(2 x)^{\circ} = 2^{\circ} x^{\circ}

= 4^{\circ} \cdot 2^{\circ} x^{\circ} x^{\circ} (3 x + 10)^{\circ} (x + 20)^{\circ}

使用指数法则:

a^{b} \cdot a^{c} = a^{b + c}

x^{\circ} x^{\circ} = x^{\circ +\circ}

= 4^{\circ} (3 x + 10)^{\circ} \cdot 2^{\circ} x^{\circ +\circ} (x + 20)^{\circ}

s im pl i f y 6.421 \cdot 1 0^{- 5} (\frac{1}{0.3048})^{2}

s im pl i f y 20 \cdot e^{- 0.8 (1)}

s im pl i f y (2 x + 1)^{2} (2 x - 1)^{2}

s im pl i f y \frac{e ^{8 x}}{e ^{5 x}}

s im pl i f y (t^{2} x^{2}) (t^{2} y^{2})