zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

化简 (2310^{-2})^33010^{-2}9.8

解答

化简

(23 \cdot 1 0^{- 2})^{3} \cdot 30 \cdot 1 0^{- 2} \cdot 9.8

解答

\frac{1788549}{50000000}

+1

十进制

0.03577098

求解步骤

(23 \cdot 1 0^{- 2})^{3} \cdot 30 \cdot 1 0^{- 2} \cdot 9.8

数字相乘:

30 \cdot 9.8 = 294

= (23 \cdot 1 0^{- 2})^{3} \cdot 294 \cdot 1 0^{- 2}

= 1 0^{- 2} \cdot 294 (23 \cdot 1 0^{- 2})^{3}

1 0^{- 2} = \frac{1}{100}

= \frac{1}{100} \cdot 294 (23 \cdot 1 0^{- 2})^{3}

使用指数法则:

(a \cdot b)^{n} = a^{n} b^{n}

(23 \cdot 1 0^{- 2})^{3} = 2 3^{3} (1 0^{- 2})^{3}

= \frac{1}{100} \cdot 294 \cdot 2 3^{3} (1 0^{- 2})^{3}

2 3^{3} = 12167

= \frac{1}{100} \cdot 294 \cdot 12167 (1 0^{- 2})^{3}

使用指数法则:

(a^{b})^{c} = a^{b c}, a \geq 0

(1 0^{- 2})^{3} = 1 0^{- 2 \cdot 3}

= \frac{1}{100} \cdot 294 \cdot 12167 \cdot 1 0^{- 2 \cdot 3}

数字相乘:

2 \cdot 3 = 6

= \frac{1}{100} \cdot 294 \cdot 12167 \cdot 1 0^{- 6}

使用指数法则:

a^{- b} = \frac{1}{a ^{b}}

1 0^{- 6} = \frac{1}{1 0 ^{6}}

= \frac{1}{100} \cdot 294 \cdot 12167 \cdot \frac{1}{1 0 ^{6}}

1 0^{6} = 1000000

= \frac{1}{100} \cdot 294 \cdot 12167 \cdot \frac{1}{1000000}

12167 \cdot \frac{1}{1000000} = \frac{12167}{1000000}

= \frac{1}{100} \cdot 294 \cdot \frac{12167}{1000000}

\frac{1}{100} \cdot 294 \cdot \frac{12167}{1000000} = \frac{1788549}{50000000}

= \frac{1788549}{50000000}

流行的例子

化简 (x-1)^2*(x+2)^2

s im pl i f y (x - 1)^{2} \cdot (x + 2)^{2}

化简 (\sqrt[5]{3})/(\sqrt[5]{16)}

s im pl i f y \frac{5 3}{5 16}

limit as x approaches infinity of ,awasderttttttt^x

x \to \infty lim (, a w a s d er tttttt t^{x})

化简 \sqrt[ 3/2 ]{8^2}*\sqrt[ 5/3 ]{32^{2/3}}

s im pl i f y \frac{3}{2} 8^{2} \cdot \frac{5}{3} 3 2^{\frac{2}{3}}

化简 (2/3 x^4-1/5 y^5)^2(2/3 x^4+1/5 y^5)^2

s im pl i f y (\frac{2}{3} x^{4} - \frac{1}{5} y^{5})^{2} (\frac{2}{3} x^{4} + \frac{1}{5} y^{5})^{2}