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Beliebt Algebra >

faktorisieren 2x^3+9x^2-27

Lösung

faktorisieren

2 x^{3} + 9 x^{2} - 27

Lösung

(x + 3)^{2} (2 x - 3)

Schritte zur Lösung

2 x^{3} + 9 x^{2} - 27

Wende den rationalen Nullstellentest an

= (x + 3) \frac{2 x ^{3} + 9 x ^{2} - 27}{x + 3}

\frac{2 x ^{3} + 9 x ^{2} - 27}{x + 3} = 2 x^{2} + 3 x - 9

= (x + 3) (2 x^{2} + 3 x - 9)

Faktorisiere

2 x^{2} + 3 x - 9 : (2 x - 3) (x + 3)

= (x + 3) (2 x - 3) (x + 3)

Wende Exponentenregel an:

aa = a^{2}

(x + 3) (x + 3) = (x + 3)^{2}

= (x + 3)^{2} (2 x - 3)

Beliebte Beispiele

vereinfachen (1+i)^{16}

s im pl i f y (1 + i)^{16}

3 v - 12 = 15

faktorisieren 4y^2-25

f a c t or 4 y^{2} - 25

(2x-3)^2+4x^2(x-7)<4(x-2)^3

(2 x - 3)^{2} + 4 x^{2} (x - 7) < 4 (x - 2)^{3}

18+(70-5x^2)=5.6x^2

18 + (70 - 5 x^{2}) = 5.6 x^{2}