What are the solutions to the equation 2000=-0.1x^2+30x ?

The solutions to the equation 2000=-0.1x^2+30x are x=100,x=200

Find the zeros of 2000=-0.1x^2+30x

The zeros of 2000=-0.1x^2+30x are x=100,x=200

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2000 = - 0.1 x^{2} + 30 x

x = 100, x = 200

Solution steps

2000 = - 0.1 x^{2} + 30 x

Multiply both sides by

10

20000 = - x^{2} + 300 x

Switch sides

- x^{2} + 300 x = 20000

Move

20000

to the left side

- x^{2} + 300 x - 20000 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 300 \pm 30 0 ^{2} - 4 ( - 1 ) ( - 20000 )}{2 ( - 1 )}

30 0^{2} - 4 (- 1) (- 20000) = 100

x_{1, 2} = \frac{- 300 \pm 100}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 300 + 100}{2 ( - 1 )}, x_{2} = \frac{- 300 - 100}{2 ( - 1 )}

x = \frac{- 300 + 100}{2 ( - 1 )} : 100

x = \frac{- 300 - 100}{2 ( - 1 )} : 200

The solutions to the quadratic equation are:

x = 100, x = 200

∣ 15 x + 9 ∣ - 5 = 1

0 = 3 x + 2

4 x + 7 \leq x + 1

6 x + 7 \leq 12 x - 7

0 = 2 x - 4

What are the solutions to the equation 2000=-0.1x^2+30x ?
The solutions to the equation 2000=-0.1x^2+30x are x=100,x=200
Find the zeros of 2000=-0.1x^2+30x
The zeros of 2000=-0.1x^2+30x are x=100,x=200