|2x+1|=5

Lösung

∣ 2 x + 1 ∣ = 5

x = - 3 or x = 2

Schritte zur Lösung

∣ 2 x + 1 ∣ = 5

Wende Absoluteregel an: Wenn

∣ u ∣ = a, a > 0

dann

u = a

u = - a

2 x + 1 = - 5 or 2 x + 1 = 5

2 x + 1 = - 5 or 2 x + 1 = 5

x = - 3 or x = 2

x (2 - x) (x - 4) \leq 0

∣ 2 x - 7 ∣ + x \geq 6

f a c t or - x^{3} + 3 x^{2} - 4

f a c t or - 2 x + 4 x + 3

s im pl i f y (\frac{1}{5})^{5}