What is log_{2}(-x)+log_{2}(1-x)-1 ?

The solution to log_{2}(-x)+log_{2}(1-x)-1 is log_{2}(-x(1-x))-1

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simplify log_{2}(-x)+log_{2}(1-x)-1

simplify

lo g_{2} (- x) + lo g_{2} (1 - x) - 1

lo g_{2} (- x (1 - x)) - 1

Solution steps

lo g_{2} (- x) + lo g_{2} (1 - x) - 1

Apply log rule:

lo g_{c} (a) + lo g_{c} (b) = lo g_{c} (ab)

lo g_{2} (- x) + lo g_{2} (1 - x) = lo g_{2} (- x (- x + 1))

= lo g_{2} (- x (1 - x)) - 1

\frac{1}{3} (ln (y) - 2 ln (z) + 3 ln (x))

lo g_{e} (\frac{5}{3}) \cdot 100

104 - 10 \cdot lo g_{10} (\frac{4 \cdot 3.14 \cdot 3 9 ^{2}}{2})

1.56 - \frac{8.314 \cdot 298.15}{2 \cdot 96485} \cdot ln (\frac{1}{0.5})

1.05 ln (\frac{700}{1450}) + 0.287 ln (\frac{50}{2}) + \frac{50}{573}

What is log_{2}(-x)+log_{2}(1-x)-1 ?
The solution to log_{2}(-x)+log_{2}(1-x)-1 is log_{2}(-x(1-x))-1