What is log_{10}(495x^4*(1-x)^{12-4}) ?

The solution to log_{10}(495x^4*(1-x)^{12-4}) is log_{10}(495)+4log_{10}(x)+8log_{10}(1-x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify log_{10}(495x^4*(1-x)^{12-4})

simplify

lo g_{10} (495 x^{4} \cdot (1 - x)^{12 - 4})

lo g_{10} (495) + 4 lo g_{10} (x) + 8 lo g_{10} (1 - x)

Solution steps

lo g_{10} (495 x^{4} (1 - x)^{12 - 4})

Apply log rule:

lo g_{c} (ab) = lo g_{c} (a) + lo g_{c} (b)

lo g_{10} (495 x^{4} (1 - x)^{12 - 4}) = lo g_{10} (495) + lo g_{10} (x^{4}) + lo g_{10} ((1 - x)^{12 - 4})

= lo g_{10} (495) + lo g_{10} (x^{4}) + lo g_{10} ((- x + 1)^{12 - 4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} (x^{4}) = 4 lo g_{10} (x)

= lo g_{10} (495) + 4 lo g_{10} (x) + lo g_{10} ((1 - x)^{12 - 4})

Apply log rule:

lo g_{a} (x^{b}) = b \cdot lo g_{a} (x)

lo g_{10} ((1 - x)^{12 - 4}) = (12 - 4) lo g_{10} (1 - x)

= lo g_{10} (495) + 4 lo g_{10} (x) + (12 - 4) lo g_{10} (1 - x)

Subtract the numbers:

12 - 4 = 8

= lo g_{10} (495) + 4 lo g_{10} (x) + 8 lo g_{10} (- x + 1)

lo g_{10} (x^{2} y)

\frac{1}{4000} ln (\frac{999}{19})

ln (4 x^{4} y^{3})

2 ln (7) + ln (2)

ln (\frac{( x - 3 ) ^{2}}{( x - 2 )})

What is log_{10}(495x^4*(1-x)^{12-4}) ?
The solution to log_{10}(495x^4*(1-x)^{12-4}) is log_{10}(495)+4log_{10}(x)+8log_{10}(1-x)