vereinfachen-5/9 (ln(10-0.9v^2)-ln(10-0.9v_{0}^2))

Lösung

vereinfachen

- \frac{5}{9} (ln (10 - 0.9 v^{2}) - ln (10 - 0.9 v_{0}^{2}))

- \frac{5}{9} ln (\frac{10 - 0.9 v ^{2}}{10 - 0.9 v _{0}^{2}})

Schritte zur Lösung

- \frac{5}{9} (ln (10 - 0.9 v^{2}) - ln (10 - 0.9 v_{0}^{2}))

Wende die log Regel an:

lo g_{c} (a) - lo g_{c} (b) = lo g_{c} (\frac{a}{b})

ln (10 - 0.9 v^{2}) - ln (10 - 0.9 v_{0}^{2}) = ln (\frac{- 0.9 v ^{2} + 10}{- 0.9 v _{0}^{2} + 10})

= - \frac{5}{9} ln (\frac{10 - 0.9 v ^{2}}{10 - 0.9 v _{0}^{2}})

j o in \frac{1}{2} lo g_{10} (11)

s im pl i f y ln (\frac{( x + 5 ) ^{2}}{( x - 9 ) ^{2} ( x ^{2} - 15 ) ^{5}})

s im pl i f y ln (sec (x) cos (y))

s im pl i f y ln (\frac{x ^{3}}{e ^{2}})

s im pl i f y - ln (0.01 1 - 0.4 6^{2})