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人気のある代数 >

(2x-1)^2-(x-3)(x+5)=(2x+3)(2x-3)

解

(2 x - 1)^{2} - (x - 3) (x + 5) = (2 x + 3) (2 x - 3)

解

x = - 3 - 34, x = 34 - 3

+1

十進法表記

x = - 8.83095 \dots, x = 2.83095 \dots

解答ステップ

(2 x - 1)^{2} - (x - 3) (x + 5) = (2 x + 3) (2 x - 3)

拡張

(2 x - 1)^{2} - (x - 3) (x + 5) : 3 x^{2} - 6 x + 16

拡張

(2 x + 3) (2 x - 3) : 4 x^{2} - 9

3 x^{2} - 6 x + 16 = 4 x^{2} - 9

9

を左側に移動します

3 x^{2} - 6 x + 25 = 4 x^{2}

4 x^{2}

を左側に移動します

- x^{2} - 6 x + 25 = 0

解くとthe二次式

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 25}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 25 = 234

x_{1, 2} = \frac{- ( - 6 ) \pm 2 34}{2 ( - 1 )}

解を分離する

x_{1} = \frac{- ( - 6 ) + 2 34}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 34}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 34}{2 ( - 1 )} : - 3 - 34

x = \frac{- ( - 6 ) - 2 34}{2 ( - 1 )} : 34 - 3

二次equationの解:

x = - 3 - 34, x = 34 - 3

グラフ

人気の例

3 x^{2} + 7 x + 5 = 3 x + 4

solvefor x,3yx^2-x^2+3=0

so l v e f or x, 3 y x^{2} - x^{2} + 3 = 0

x^{2} + 8 x + 8 + 8 = 0

solvefor x,x^2+y^2=10x-6y-34

so l v e f or x, x^{2} + y^{2} = 10 x - 6 y - 34

(x - 6) (x + 2) = 9