-3t^2+12t-9=0

解

- 3 t^{2} + 12 t - 9 = 0

t = 1, t = 3

解答ステップ

- 3 t^{2} + 12 t - 9 = 0

解くとthe二次式

t_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 3 ) ( - 9 )}{2 ( - 3 )}

1 2^{2} - 4 (- 3) (- 9) = 6

t_{1, 2} = \frac{- 12 \pm 6}{2 ( - 3 )}

解を分離する

t_{1} = \frac{- 12 + 6}{2 ( - 3 )}, t_{2} = \frac{- 12 - 6}{2 ( - 3 )}

t = \frac{- 12 + 6}{2 ( - 3 )} : 1

t = \frac{- 12 - 6}{2 ( - 3 )} : 3

二次equationの解:

t = 1, t = 3