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受欢迎的代数 >

x^2-2ax+1=0

解答

x^{2} - 2 a x + 1 = 0

解答

x = a + a^{2} - 1, x = a - a^{2} - 1

求解步骤

x^{2} - 2 a x + 1 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 a ) \pm ( - 2 a ) ^{2} - 4 \cdot 1 \cdot 1}{2 \cdot 1}

化简

(- 2 a)^{2} - 4 \cdot 1 \cdot 1 : 2 a^{2} - 1

x_{1, 2} = \frac{- ( - 2 a ) \pm 2 a ^{2} - 1}{2 \cdot 1}

将解分隔开

x_{1} = \frac{- ( - 2 a ) + 2 a ^{2} - 1}{2 \cdot 1}, x_{2} = \frac{- ( - 2 a ) - 2 a ^{2} - 1}{2 \cdot 1}

x = \frac{- ( - 2 a ) + 2 a ^{2} - 1}{2 \cdot 1} : a + a^{2} - 1

x = \frac{- ( - 2 a ) - 2 a ^{2} - 1}{2 \cdot 1} : a - a^{2} - 1

二次方程组的解是:

x = a + a^{2} - 1, x = a - a^{2} - 1

作图

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