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人気のある代数 >

solvefor x,f(x+1)=(x+1)^2-4

解

解く

x, f (x + 1) = (x + 1)^{2} - 4

解

x = \frac{- 2 + f + f ^{2} + 16}{2}, x = \frac{- 2 + f - f ^{2} + 16}{2}

解答ステップ

f (x + 1) = (x + 1)^{2} - 4

拡張

f (x + 1) : x f + f

拡張

(x + 1)^{2} - 4 : x^{2} + 2 x - 3

x f + f = x^{2} + 2 x - 3

辺を交換する

x^{2} + 2 x - 3 = x f + f

f

を左側に移動します

x^{2} + 2 x - 3 - f = x f

x f

を左側に移動します

x^{2} + 2 x - 3 - f - x f = 0

標準的な形式で書く

a x^{2} + b x + c = 0

x^{2} + (2 - f) x - 3 - f = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 2 - f ) \pm ( 2 - f ) ^{2} - 4 \cdot 1 \cdot ( - 3 - f )}{2 \cdot 1}

簡素化

(2 - f)^{2} - 4 \cdot 1 \cdot (- 3 - f) : f^{2} + 16

x_{1, 2} = \frac{- ( 2 - f ) \pm f ^{2} + 16}{2 \cdot 1}

解を分離する

x_{1} = \frac{- ( 2 - f ) + f ^{2} + 16}{2 \cdot 1}, x_{2} = \frac{- ( 2 - f ) - f ^{2} + 16}{2 \cdot 1}

x = \frac{- ( 2 - f ) + f ^{2} + 16}{2 \cdot 1} : \frac{- 2 + f + f ^{2} + 16}{2}

x = \frac{- ( 2 - f ) - f ^{2} + 16}{2 \cdot 1} : \frac{- 2 + f - f ^{2} + 16}{2}

二次equationの解:

x = \frac{- 2 + f + f ^{2} + 16}{2}, x = \frac{- 2 + f - f ^{2} + 16}{2}

グラフ

人気の例

(x+8)^2+(x-8)^2=x^2+132

(x + 8)^{2} + (x - 8)^{2} = x^{2} + 132

completesquare-3x^2+12x+8

co m pl e t es q u a re - 3 x^{2} + 12 x + 8

solvefor x,y^2x^2-4x^2=-y^2-9

so l v e f or x, y^{2} x^{2} - 4 x^{2} = - y^{2} - 9

(2x-3)^2-(3x+1)(3x-1)=(x-7)(x+2)+24

(2 x - 3)^{2} - (3 x + 1) (3 x - 1) = (x - 7) (x + 2) + 24

1/2 x^2-x-1=-x+1

\frac{1}{2} x^{2} - x - 1 = - x + 1