What are the solutions to the equation solvefor a,g(a+b)=(a+b)^2-4(a+b) ?

The solutions to the equation solvefor a,g(a+b)=(a+b)^2-4(a+b) are a=-b,a=g-b+4

Find the zeros of solvefor a,g(a+b)=(a+b)^2-4(a+b)

The zeros of solvefor a,g(a+b)=(a+b)^2-4(a+b) are a=-b,a=g-b+4

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solve for

a, g (a + b) = (a + b)^{2} - 4 (a + b)

a = - b, a = g - b + 4

Solution steps

g (a + b) = (a + b)^{2} - 4 (a + b)

Switch sides

(a + b)^{2} - 4 (a + b) = g (a + b)

Move

g (a + b)

to the left side

(a + b)^{2} - 4 (a + b) - g (a + b) = 0

Factor

(a + b)^{2} - 4 (a + b) - g (a + b) : (a + b) (a - g + b - 4)

(a + b) (a - g + b - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

a + b = 0 or a - g + b - 4 = 0

Solve

a + b = 0 : a = - b

Solve

a - g + b - 4 = 0 : a = g - b + 4

The solutions to the quadratic equation are:

a = - b, a = g - b + 4

2 \cdot (x^{2} + 10) = 22

x, x^{2} - x^{2} y^{3} + 5 y^{4} = 0

z^{2} + 8 z - 9 = 0

x^{2} - 5 x + 2 = - 3 x + 10

x, x^{2} + 6 x - 2 = 0

What are the solutions to the equation solvefor a,g(a+b)=(a+b)^2-4(a+b) ?
The solutions to the equation solvefor a,g(a+b)=(a+b)^2-4(a+b) are a=-b,a=g-b+4
Find the zeros of solvefor a,g(a+b)=(a+b)^2-4(a+b)
The zeros of solvefor a,g(a+b)=(a+b)^2-4(a+b) are a=-b,a=g-b+4