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人気のある代数 >

solvefor x,F=(m-2)x^2+(n-1)x+(p-3)

解

解く

x, F = (m - 2) x^{2} + (n - 1) x + (p - 3)

解

x = \frac{- n + 1 + 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}, x = \frac{- n + 1 - 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}; m \neq = 2

解答ステップ

F = (m - 2) x^{2} + (n - 1) x + (p - 3)

拡張

(m - 2) x^{2} + (n - 1) x + (p - 3) : m x^{2} - 2 x^{2} + n x - x + p - 3

F = m x^{2} - 2 x^{2} + n x - x + p - 3

辺を交換する

m x^{2} - 2 x^{2} + n x - x + p - 3 = F

F

を左側に移動します

m x^{2} - 2 x^{2} + n x - x + p - 3 - F = 0

標準的な形式で書く

a x^{2} + b x + c = 0

(m - 2) x^{2} + (n - 1) x + p - 3 - F = 0

解くとthe二次式

x_{1, 2} = \frac{- ( n - 1 ) \pm ( n - 1 ) ^{2} - 4 ( m - 2 ) ( p - 3 - F )}{2 ( m - 2 )}

簡素化

(n - 1)^{2} - 4 (m - 2) (p - 3 - F) : 4 m F - 8 F + 12 m + n^{2} + 8 p - 4 m p - 2 n - 23

x_{1, 2} = \frac{- ( n - 1 ) \pm 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}; m \neq = 2

解を分離する

x_{1} = \frac{- ( n - 1 ) + 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}, x_{2} = \frac{- ( n - 1 ) - 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}

x = \frac{- ( n - 1 ) + 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )} : \frac{- n + 1 + 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}

x = \frac{- ( n - 1 ) - 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )} : \frac{- n + 1 - 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}

二次equationの解:

x = \frac{- n + 1 + 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}, x = \frac{- n + 1 - 4 m F - 8 F + 12 m + n ^{2} + 8 p - 4 m p - 2 n - 23}{2 ( m - 2 )}; m \neq = 2

グラフ

人気の例

(x + 9)^{2} = 12

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so l v e f or x, x^{2} + 4 x - 2 a y + 2 (2 - a^{2}) = 0

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因数 4x^2+16x=0

f a c t or 4 x^{2} + 16 x = 0

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