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受欢迎的代数 >

2X^2-(-10)=-X

解答

2 X^{2} - (- 10) = - X

解答

X = - \frac{1}{4} + i \frac{79}{4}, X = - \frac{1}{4} - i \frac{79}{4}

求解步骤

2 X^{2} - (- 10) = - X

整理后得

2 X^{2} + 10 = - X

将

X

para o lado esquerdo

2 X^{2} + 10 + X = 0

改写成标准形式

a x^{2} + b x + c = 0

2 X^{2} + X + 10 = 0

使用求根公式求解

X_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 \cdot 10}{2 \cdot 2}

化简

1^{2} - 4 \cdot 2 \cdot 10 : 79 i

X_{1, 2} = \frac{- 1 \pm 79 i}{2 \cdot 2}

将解分隔开

X_{1} = \frac{- 1 + 79 i}{2 \cdot 2}, X_{2} = \frac{- 1 - 79 i}{2 \cdot 2}

X = \frac{- 1 + 79 i}{2 \cdot 2} : - \frac{1}{4} + i \frac{79}{4}

X = \frac{- 1 - 79 i}{2 \cdot 2} : - \frac{1}{4} - i \frac{79}{4}

二次方程组的解是:

X = - \frac{1}{4} + i \frac{79}{4}, X = - \frac{1}{4} - i \frac{79}{4}

作图

流行的例子

8 x^{2} - 8 x - 5 = 0

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(2x+1)^2=(5x-1)(5x+1)

(2 x + 1)^{2} = (5 x - 1) (5 x + 1)

r^2=(sqrt(3))^2+(-1)^2

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