3r^2-4050r+1362500=0

解

3 r^{2} - 4050 r + 1362500 = 0

r = \frac{25 ( 81 + 21 )}{3}, r = \frac{25 ( 81 - 21 )}{3}

十進法表記

r = 713.18813 \dots, r = 636.81186 \dots

解答ステップ

3 r^{2} - 4050 r + 1362500 = 0

解くとthe二次式

r_{1, 2} = \frac{- ( - 4050 ) \pm ( - 4050 ) ^{2} - 4 \cdot 3 \cdot 1362500}{2 \cdot 3}

(- 4050)^{2} - 4 \cdot 3 \cdot 1362500 = 5021

r_{1, 2} = \frac{- ( - 4050 ) \pm 50 21}{2 \cdot 3}

解を分離する

r_{1} = \frac{- ( - 4050 ) + 50 21}{2 \cdot 3}, r_{2} = \frac{- ( - 4050 ) - 50 21}{2 \cdot 3}

r = \frac{- ( - 4050 ) + 50 21}{2 \cdot 3} : \frac{25 ( 81 + 21 )}{3}

r = \frac{- ( - 4050 ) - 50 21}{2 \cdot 3} : \frac{25 ( 81 - 21 )}{3}

二次equationの解:

r = \frac{25 ( 81 + 21 )}{3}, r = \frac{25 ( 81 - 21 )}{3}