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受欢迎的代数 >

solvefor a,a(a-b)=31

解答

求解

a, a (a - b) = 31

解答

a = \frac{b + b ^{2} + 124}{2}, a = \frac{b - b ^{2} + 124}{2}

求解步骤

a (a - b) = 31

展开

a (a - b) : a^{2} - ab

a^{2} - ab = 31

将

31

para o lado esquerdo

a^{2} - ab - 31 = 0

改写成标准形式

a x^{2} + b x + c = 0

a^{2} - ba - 31 = 0

使用求根公式求解

a_{1, 2} = \frac{- ( - b ) \pm ( - b ) ^{2} - 4 \cdot 1 \cdot ( - 31 )}{2 \cdot 1}

化简

(- b)^{2} - 4 \cdot 1 \cdot (- 31) : b^{2} + 124

a_{1, 2} = \frac{- ( - b ) \pm b ^{2} + 124}{2 \cdot 1}

将解分隔开

a_{1} = \frac{- ( - b ) + b ^{2} + 124}{2 \cdot 1}, a_{2} = \frac{- ( - b ) - b ^{2} + 124}{2 \cdot 1}

a = \frac{- ( - b ) + b ^{2} + 124}{2 \cdot 1} : \frac{b + b ^{2} + 124}{2}

a = \frac{- ( - b ) - b ^{2} + 124}{2 \cdot 1} : \frac{b - b ^{2} + 124}{2}

二次方程组的解是:

a = \frac{b + b ^{2} + 124}{2}, a = \frac{b - b ^{2} + 124}{2}

作图

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