solvefor x,(λ^2-25)x^2+(λ^2-36)y^2=λ

解

解く

x, (λ^{2} - 25) x^{2} + (λ^{2} - 36) y^{2} = λ

x = \frac{λ - y ^{2} ( λ ^{2} - 36 )}{λ ^{2} - 25}, x = - \frac{λ - y ^{2} ( λ ^{2} - 36 )}{λ ^{2} - 25}; λ \neq = 5, λ \neq = - 5

解答ステップ

(λ^{2} - 25) x^{2} + (λ^{2} - 36) y^{2} = λ

(λ^{2} - 36) y^{2}

を右側に移動します

(λ^{2} - 25) x^{2} = λ - (λ^{2} - 36) y^{2}

以下で両辺を割る

λ^{2} - 25; λ \neq = 5, λ \neq = - 5

x^{2} = \frac{λ - y ^{2} ( λ ^{2} - 36 )}{λ ^{2} - 25}; λ \neq = 5, λ \neq = - 5

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = \frac{λ - y ^{2} ( λ ^{2} - 36 )}{λ ^{2} - 25}, x = - \frac{λ - y ^{2} ( λ ^{2} - 36 )}{λ ^{2} - 25}; λ \neq = 5, λ \neq = - 5