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受欢迎的代数 >

solvefor x,f(x+2)=3x^2-2x+1

解答

求解

x, f (x + 2) = 3 x^{2} - 2 x + 1

解答

x = \frac{2 + f + f ^{2} + 28 f - 8}{6}, x = \frac{2 + f - f ^{2} + 28 f - 8}{6}

求解步骤

f (x + 2) = 3 x^{2} - 2 x + 1

展开

f (x + 2) : x f + 2 f

x f + 2 f = 3 x^{2} - 2 x + 1

交换两边

3 x^{2} - 2 x + 1 = x f + 2 f

将

2 f

para o lado esquerdo

3 x^{2} - 2 x + 1 - 2 f = x f

将

x f

para o lado esquerdo

3 x^{2} - 2 x + 1 - 2 f - x f = 0

改写成标准形式

a x^{2} + b x + c = 0

3 x^{2} - (2 + f) x + 1 - 2 f = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 2 - f ) \pm ( - 2 - f ) ^{2} - 4 \cdot 3 ( 1 - 2 f )}{2 \cdot 3}

化简

(- 2 - f)^{2} - 4 \cdot 3 (1 - 2 f) : f^{2} + 28 f - 8

x_{1, 2} = \frac{- ( - 2 - f ) \pm f ^{2} + 28 f - 8}{2 \cdot 3}

将解分隔开

x_{1} = \frac{- ( - 2 - f ) + f ^{2} + 28 f - 8}{2 \cdot 3}, x_{2} = \frac{- ( - 2 - f ) - f ^{2} + 28 f - 8}{2 \cdot 3}

x = \frac{- ( - 2 - f ) + f ^{2} + 28 f - 8}{2 \cdot 3} : \frac{2 + f + f ^{2} + 28 f - 8}{6}

x = \frac{- ( - 2 - f ) - f ^{2} + 28 f - 8}{2 \cdot 3} : \frac{2 + f - f ^{2} + 28 f - 8}{6}

二次方程组的解是:

x = \frac{2 + f + f ^{2} + 28 f - 8}{6}, x = \frac{2 + f - f ^{2} + 28 f - 8}{6}

作图

流行的例子

2 m^{2} + 7 m - 9 = 0

π \cdot r^{2} = 154

4 x^{2} - 6 x = - 1

2(x^2+4)+7(x^2-56)=1

2 (x^{2} + 4) + 7 (x^{2} - 56) = 1

solvefor x,f=x^2+3yg

so l v e f or x, f = x^{2} + 3 y g