2x^2+28x-64=0

解

2 x^{2} + 28 x - 64 = 0

x = 2, x = - 16

解答ステップ

2 x^{2} + 28 x - 64 = 0

解くとthe二次式

x_{1, 2} = \frac{- 28 \pm 2 8 ^{2} - 4 \cdot 2 ( - 64 )}{2 \cdot 2}

2 8^{2} - 4 \cdot 2 (- 64) = 36

x_{1, 2} = \frac{- 28 \pm 36}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 28 + 36}{2 \cdot 2}, x_{2} = \frac{- 28 - 36}{2 \cdot 2}

x = \frac{- 28 + 36}{2 \cdot 2} : 2

x = \frac{- 28 - 36}{2 \cdot 2} : - 16

二次equationの解:

x = 2, x = - 16