What are the solutions to the equation c^2+5c-24=0 ?

The solutions to the equation c^2+5c-24=0 are c=3,c=-8

Find the zeros of c^2+5c-24=0

The zeros of c^2+5c-24=0 are c=3,c=-8

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c^{2} + 5 c - 24 = 0

c = 3, c = - 8

Solution steps

c^{2} + 5 c - 24 = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

5^{2} - 4 \cdot 1 \cdot (- 24) = 11

c_{1, 2} = \frac{- 5 \pm 11}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- 5 + 11}{2 \cdot 1}, c_{2} = \frac{- 5 - 11}{2 \cdot 1}

c = \frac{- 5 + 11}{2 \cdot 1} : 3

c = \frac{- 5 - 11}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

c = 3, c = - 8

18 x^{2} + 24 x = - 8

12 x^{2} - 27 = 0

(3 x - 4)^{2} = 5 x - 6

m^{2} = - 9 m

(9.8) (6) = \frac{1}{2} v^{2}

What are the solutions to the equation c^2+5c-24=0 ?
The solutions to the equation c^2+5c-24=0 are c=3,c=-8
Find the zeros of c^2+5c-24=0
The zeros of c^2+5c-24=0 are c=3,c=-8