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受欢迎的代数 >

5t^2+1.3t-0.7=0

解答

5 t^{2} + 1.3 t - 0.7 = 0

解答

t = \frac{- 13 + 1569}{100}, t = \frac{- 13 - 1569}{100}

+1

十进制

t = 0.26610 \dots, t = - 0.52610 \dots

求解步骤

5 t^{2} + 1.3 t - 0.7 = 0

在两边乘以

10

50 t^{2} + 13 t - 7 = 0

使用求根公式求解

t_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 50 ( - 7 )}{2 \cdot 50}

1 3^{2} - 4 \cdot 50 (- 7) = 1569

t_{1, 2} = \frac{- 13 \pm 1569}{2 \cdot 50}

将解分隔开

t_{1} = \frac{- 13 + 1569}{2 \cdot 50}, t_{2} = \frac{- 13 - 1569}{2 \cdot 50}

t = \frac{- 13 + 1569}{2 \cdot 50} : \frac{- 13 + 1569}{100}

t = \frac{- 13 - 1569}{2 \cdot 50} : \frac{- 13 - 1569}{100}

二次方程组的解是:

t = \frac{- 13 + 1569}{100}, t = \frac{- 13 - 1569}{100}

作图

流行的例子

solvefor y,(10-x)y^2=x^3

so l v e f or y, (10 - x) y^{2} = x^{3}

x^{2} + 5 x - 2 = 5 x + 2

3 x^{2} + 2 x - 13 = 0

s^{2} b + (s + 10) a = 1

1.9*10^{-6}x^2+0.013x+1=0

1.9 \cdot 1 0^{- 6} x^{2} + 0.013 x + 1 = 0