|x-12|>24

Lösung

∣ x - 12 ∣ > 24

x < - 12 or x > 36

Intervall-Notation

(- \infty, - 12) \cup (36, \infty)

Schritte zur Lösung

∣ x - 12 ∣ > 24

Wende Absoluteregel an: Wenn

∣ u ∣ > a, a > 0

dann

u < - a

u > a

x - 12 < - 24 or x - 12 > 24

x - 12 < - 24 or x - 12 > 24

x < - 12 or x > 36

3 = \frac{1}{3} (10 x - 12)

2 (x + 4) - 4 (1 - 2 x) = 0

s im pl i f y 51 2^{\frac{1}{3}}

\frac{1}{6} < x - \frac{11}{12} < 6

n^{2} + 9 n + 20 = 0