What are the solutions to the equation 2x^2-x-78=0 ?

The solutions to the equation 2x^2-x-78=0 are x= 13/2 ,x=-6

Find the zeros of 2x^2-x-78=0

The zeros of 2x^2-x-78=0 are x= 13/2 ,x=-6

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2 x^{2} - x - 78 = 0

x = \frac{13}{2}, x = - 6

Decimal Notation

x = 6.5, x = - 6

Solution steps

2 x^{2} - x - 78 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 ( - 78 )}{2 \cdot 2}

(- 1)^{2} - 4 \cdot 2 (- 78) = 25

x_{1, 2} = \frac{- ( - 1 ) \pm 25}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 25}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 25}{2 \cdot 2}

x = \frac{- ( - 1 ) + 25}{2 \cdot 2} : \frac{13}{2}

x = \frac{- ( - 1 ) - 25}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = \frac{13}{2}, x = - 6

6 x^{2} + 3 x = 1296

(s^{2} - 4) = 0

(x - 1) (x + 4) + 4 = 0

\frac{49 + 25 - 9}{2 \cdot 7 \cdot 5} = \frac{49 + 49 - x ^{2}}{2 \cdot 7 \cdot 7}

x^{2} - 6 x - 4 = 0

What are the solutions to the equation 2x^2-x-78=0 ?
The solutions to the equation 2x^2-x-78=0 are x= 13/2 ,x=-6
Find the zeros of 2x^2-x-78=0
The zeros of 2x^2-x-78=0 are x= 13/2 ,x=-6