r^2+10r+24=0

解

r^{2} + 10 r + 24 = 0

r = - 4, r = - 6

解答ステップ

r^{2} + 10 r + 24 = 0

解くとthe二次式

r_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 24}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 24 = 2

r_{1, 2} = \frac{- 10 \pm 2}{2 \cdot 1}

解を分離する

r_{1} = \frac{- 10 + 2}{2 \cdot 1}, r_{2} = \frac{- 10 - 2}{2 \cdot 1}

r = \frac{- 10 + 2}{2 \cdot 1} : - 4

r = \frac{- 10 - 2}{2 \cdot 1} : - 6

二次equationの解:

r = - 4, r = - 6