x^2+(7-26/3)^2=64

解

x^{2} + (7 - \frac{26}{3})^{2} = 64

x = \frac{551}{3}, x = - \frac{551}{3}

十進法表記

x = 7.82446 \dots, x = - 7.82446 \dots

解答ステップ

x^{2} + (7 - \frac{26}{3})^{2} = 64

(7 - \frac{26}{3})^{2}

を右側に移動します

x^{2} = 64 - (7 - \frac{26}{3})^{2}

簡素化

64 - (7 - \frac{26}{3})^{2} : \frac{551}{9}

x^{2} = f (a)

の場合, 解は

x = f (a), - f (a)

x = \frac{551}{9}, x = - \frac{551}{9}

\frac{551}{9} = \frac{551}{3}

- \frac{551}{9} = - \frac{551}{3}

x = \frac{551}{3}, x = - \frac{551}{3}