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受欢迎的代数 >

completesquare 28=28T^2-179T+89

解答

28 = 28 T^{2} - 179 T + 89

解答

T = \frac{3 2801 + 179}{56}, T = \frac{- 3 2801 + 179}{56}

+1

十进制

T = 6.03166 \dots, T = 0.36118 \dots

求解步骤

28 = 28 T^{2} - 179 T + 89

交换两边

28 T^{2} - 179 T + 89 = 28

将

89

到右边

28 T^{2} - 179 T = - 61

两边除以

28

\frac{28 T ^{2} - 179 T}{28} = \frac{- 61}{28}

T^{2} - \frac{179 T}{28} = - \frac{61}{28}

改写为形式

(x + a)^{2} = b

(T - \frac{179}{56})^{2} = \frac{25209}{3136}

若

f^{2} (x) = a

，解为

f (x) = a, - a

解

T - \frac{179}{56} = \frac{25209}{3136} : T = \frac{3 2801 + 179}{56}

解

T - \frac{179}{56} = - \frac{25209}{3136} : T = \frac{- 3 2801 + 179}{56}

二次方程组的解是:

T = \frac{3 2801 + 179}{56}, T = \frac{- 3 2801 + 179}{56}

作图

流行的例子

0 = 144 - 16 t^{2}

x^{2} + 4 x + 4 = 4

-1/4 f^2+5/4 f+15/4 =0

- \frac{1}{4} f^{2} + \frac{5}{4} f + \frac{15}{4} = 0

6 x^{2} = 18 - 23 x

solvefor x,x^2-6x+11=0

so l v e f or x, x^{2} - 6 x + 11 = 0