zs

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

受欢迎的代数 >

(5x-4)2-(3x+2)(2x-1)=20x(x-2)+27

解答

(5 x - 4) 2 - (3 x + 2) (2 x - 1) = 20 x (x - 2) + 27

解答

x = \frac{49}{52} - i \frac{1031}{52}, x = \frac{49}{52} + i \frac{1031}{52}

求解步骤

(5 x - 4) \cdot 2 - (3 x + 2) (2 x - 1) = 20 x (x - 2) + 27

展开

(5 x - 4) \cdot 2 - (3 x + 2) (2 x - 1) : - 6 x^{2} + 9 x - 6

展开

20 x (x - 2) + 27 : 20 x^{2} - 40 x + 27

- 6 x^{2} + 9 x - 6 = 20 x^{2} - 40 x + 27

将

27

para o lado esquerdo

- 6 x^{2} + 9 x - 33 = 20 x^{2} - 40 x

将

40 x

para o lado esquerdo

- 6 x^{2} + 49 x - 33 = 20 x^{2}

将

20 x^{2}

para o lado esquerdo

- 26 x^{2} + 49 x - 33 = 0

使用求根公式求解

x_{1, 2} = \frac{- 49 \pm 4 9 ^{2} - 4 ( - 26 ) ( - 33 )}{2 ( - 26 )}

化简

4 9^{2} - 4 (- 26) (- 33) : 1031 i

x_{1, 2} = \frac{- 49 \pm 1031 i}{2 ( - 26 )}

将解分隔开

x_{1} = \frac{- 49 + 1031 i}{2 ( - 26 )}, x_{2} = \frac{- 49 - 1031 i}{2 ( - 26 )}

x = \frac{- 49 + 1031 i}{2 ( - 26 )} : \frac{49}{52} - i \frac{1031}{52}

x = \frac{- 49 - 1031 i}{2 ( - 26 )} : \frac{49}{52} + i \frac{1031}{52}

二次方程组的解是:

x = \frac{49}{52} - i \frac{1031}{52}, x = \frac{49}{52} + i \frac{1031}{52}

作图

流行的例子

solvefor s,A=6(s+2)^2

so l v e f or s, A = 6 (s + 2)^{2}

(10+2s)^2+(5+s)^2+2^2=9

(10 + 2 s)^{2} + (5 + s)^{2} + 2^{2} = 9

2 x^{1} - x^{2} + 3 = 1

4^{2} + x^{2} = 1 1^{2}

3 y^{2} - 7 y = 3