-0.0006t^2+0.048t-0.29=0

Lösung

- 0.0006 t^{2} + 0.048 t - 0.29 = 0

t = \frac{0.048 - 0.001608}{0.0012}, t = \frac{0.048 + 0.001608}{0.0012}

Dezimale

t = 6.58343 \dots, t = 73.41656 \dots

Schritte zur Lösung

- 0.0006 t^{2} + 0.048 t - 0.29 = 0

Löse mit der quadratischen Formel

t_{1, 2} = \frac{- 0.048 \pm 0.04 8 ^{2} - 4 ( - 0.0006 ) ( - 0.29 )}{2 ( - 0.0006 )}

0.04 8^{2} - 4 (- 0.0006) (- 0.29) = 0.001608

t_{1, 2} = \frac{- 0.048 \pm 0.001608}{2 ( - 0.0006 )}

Trenne die Lösungen

t_{1} = \frac{- 0.048 + 0.001608}{2 ( - 0.0006 )}, t_{2} = \frac{- 0.048 - 0.001608}{2 ( - 0.0006 )}

t = \frac{- 0.048 + 0.001608}{2 ( - 0.0006 )} : \frac{0.048 - 0.001608}{0.0012}

t = \frac{- 0.048 - 0.001608}{2 ( - 0.0006 )} : \frac{0.048 + 0.001608}{0.0012}

Die Lösungen für die quadratische Gleichung sind:

t = \frac{0.048 - 0.001608}{0.0012}, t = \frac{0.048 + 0.001608}{0.0012}

so l v e f or x, 2 x^{2} - 5 x - 4 = 0

2 (x^{2} + 2 x + 1) + 4 x = - (x - 1)^{2}

- 5 x^{2} = - 80

3 x^{2} - 12 x = - 2

- 2 (x - 3)^{2} + 4 = 0