k^2+16k-17=0

解

k^{2} + 16 k - 17 = 0

k = 1, k = - 17

解答ステップ

k^{2} + 16 k - 17 = 0

解くとthe二次式

k_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 17 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 17) = 18

k_{1, 2} = \frac{- 16 \pm 18}{2 \cdot 1}

解を分離する

k_{1} = \frac{- 16 + 18}{2 \cdot 1}, k_{2} = \frac{- 16 - 18}{2 \cdot 1}

k = \frac{- 16 + 18}{2 \cdot 1} : 1

k = \frac{- 16 - 18}{2 \cdot 1} : - 17

二次equationの解:

k = 1, k = - 17