What are the solutions to the equation x^2=(-1)/3 ?

The solutions to the equation x^2=(-1)/3 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

Find the zeros of x^2=(-1)/3

The zeros of x^2=(-1)/3 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i

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x^{2} = \frac{- 1}{3}

x = \frac{1}{3} i, x = - \frac{1}{3} i

Solution steps

x^{2} = \frac{- 1}{3}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

x^{2} = - \frac{1}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{3}, x = - - \frac{1}{3}

- \frac{1}{3} = \frac{1}{3} i

- - \frac{1}{3} = - \frac{1}{3} i

x = \frac{1}{3} i, x = - \frac{1}{3} i

2 x - 25 = - x^{2} - 16

4 x^{2} - 5 x + 2 = 0

10 x^{2} + 20 x + 5 = 0

- 2 p^{2} + 3 p + 6 = 0

- 9 x^{2} + x - 8 = 0

What are the solutions to the equation x^2=(-1)/3 ?
The solutions to the equation x^2=(-1)/3 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i
Find the zeros of x^2=(-1)/3
The zeros of x^2=(-1)/3 are x= 1/(sqrt(3))i,x=-1/(sqrt(3))i