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受欢迎的代数 >

5t^2+1-7t=0

解答

5 t^{2} + 1 - 7 t = 0

解答

t = \frac{7 + 29}{10}, t = \frac{7 - 29}{10}

+1

十进制

t = 1.23851 \dots, t = 0.16148 \dots

求解步骤

5 t^{2} + 1 - 7 t = 0

改写成标准形式

a x^{2} + b x + c = 0

5 t^{2} - 7 t + 1 = 0

使用求根公式求解

t_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 5 \cdot 1}{2 \cdot 5}

(- 7)^{2} - 4 \cdot 5 \cdot 1 = 29

t_{1, 2} = \frac{- ( - 7 ) \pm 29}{2 \cdot 5}

将解分隔开

t_{1} = \frac{- ( - 7 ) + 29}{2 \cdot 5}, t_{2} = \frac{- ( - 7 ) - 29}{2 \cdot 5}

t = \frac{- ( - 7 ) + 29}{2 \cdot 5} : \frac{7 + 29}{10}

t = \frac{- ( - 7 ) - 29}{2 \cdot 5} : \frac{7 - 29}{10}

二次方程组的解是:

t = \frac{7 + 29}{10}, t = \frac{7 - 29}{10}

作图

流行的例子

2 x^{2} - 24 x + 33 = 0

5y^2+3sqrt(5)+2=0

5 y^{2} + 35 + 2 = 0

3 s^{2} - 9 s - 1 = 0

2 x^{2} = - 7 x - 6

completesquare h^2-10h-4=0

co m pl e t es q u a re h^{2} - 10 h - 4 = 0