What are the solutions to the equation 7x^2+13x+6=0 ?

The solutions to the equation 7x^2+13x+6=0 are x=-6/7 ,x=-1

Find the zeros of 7x^2+13x+6=0

The zeros of 7x^2+13x+6=0 are x=-6/7 ,x=-1

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7 x^{2} + 13 x + 6 = 0

x = - \frac{6}{7}, x = - 1

Decimal Notation

x = - 0.85714 \dots, x = - 1

Solution steps

7 x^{2} + 13 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 13 \pm 1 3 ^{2} - 4 \cdot 7 \cdot 6}{2 \cdot 7}

1 3^{2} - 4 \cdot 7 \cdot 6 = 1

x_{1, 2} = \frac{- 13 \pm 1}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- 13 + 1}{2 \cdot 7}, x_{2} = \frac{- 13 - 1}{2 \cdot 7}

x = \frac{- 13 + 1}{2 \cdot 7} : - \frac{6}{7}

x = \frac{- 13 - 1}{2 \cdot 7} : - 1

The solutions to the quadratic equation are:

x = - \frac{6}{7}, x = - 1

2 x^{2} - 11 x + 5 = 0

x, y = 3 x^{2} - 1

9 y^{2} = 3 (3 - 3) 2

0.05 x^{2} + 2 x + 100 = 0

(x^{2} - 81) = 0

What are the solutions to the equation 7x^2+13x+6=0 ?
The solutions to the equation 7x^2+13x+6=0 are x=-6/7 ,x=-1
Find the zeros of 7x^2+13x+6=0
The zeros of 7x^2+13x+6=0 are x=-6/7 ,x=-1