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受欢迎的代数 >

(9(t-9)}{10}+1=t-\frac{3t-5)/2+23/5

解答

\frac{9 ( t - 9 )}{10} + 1 = t - \frac{3 t - 5}{2} + \frac{23}{5}

解答

t = \frac{71}{7}

+1

十进制

t = 10.14285 \dots

求解步骤

\frac{9 ( t - 9 )}{10} + 1 = t - \frac{3 t - 5}{2} + \frac{23}{5}

乘以最小公倍数

9 (t - 9) + 10 = 10 t - 5 (3 t - 5) + 46

展开

9 (t - 9) + 10 : 9 t - 71

展开

10 t - 5 (3 t - 5) + 46 : - 5 t + 71

9 t - 71 = - 5 t + 71

将

71

到右边

9 t = - 5 t + 142

将

5 t

para o lado esquerdo

14 t = 142

两边除以

14

t = \frac{71}{7}

作图

流行的例子

(x+1/9)(x+5/3)=(x+5/3)(x+10)

(x + \frac{1}{9}) (x + \frac{5}{3}) = (x + \frac{5}{3}) (x + 10)

solvefor y,y= 6/5 (1-e^{-20t})

so l v e f or y, y = \frac{6}{5} (1 - e^{- 20 t})

log_{2}(4(90)+6)+log_{2}(90)=2

lo g_{2} (4 (90) + 6) + lo g_{2} (90) = 2

solvefor k,13t=(9k)/4+17

so l v e f or k, 13 t = \frac{9 k}{4} + 17

3 (h - 6) = 2 (5 - 2 h)