solvefor a,ax^{b+3}-3x^5=7x^{c+2}

解答

求解

a, a x^{b + 3} - 3 x^{5} = 7 x^{c + 2}

a = x^{- b - 1} (7 x^{c} + 3 x^{3})

求解步骤

a x^{b + 3} - 3 x^{5} = 7 x^{c + 2}

将

3 x^{5}

到右边

a x^{b + 3} = 7 x^{c + 2} + 3 x^{5}

两边除以

x^{b + 3}

a = x^{- b - 1} (7 x^{c} + 3 x^{3})

so l v e f or x, 5 x = a x + w

A x = b

- 6 x + 2 x + 9 = - 2 x + 4 - x

6 (b + 5) = 18

3 x - \frac{2 x - 10}{4} = 2 (x - 2) + 9